Expanding the method

We saw on the previous page, AT-1 = A-1T. Or AT-1T = A-1. And the inverse was obtained using column operations directly on the matrix without the need to take the transpose or do a transpose of the resulting inverse to get the solution to the problem. On this page we combine row and column operations, using the same square non-singular matrix.

Column and Row operations

We begin with the matrix from the previous page, augmented with an identity matrix of the appropriate rank for the operations and begin.

101
01-1
10-1
100
010
001
100
010
001

Subtract row 1 from row 3.

101
01-1
00-2
100
010
-101
100
010
001

Subtract column 1 from column 3.

100
01-1
00-2
100
010
-101
10-1
010
001

Add column 2 to column 3.

100
010
00-2
100
010
-101
10-1
011
001

Divide through row 3 by -2.

100
010
001
100
010
1/20-1/2
10-1
011
001

Combine partial operations

To combine the column and row operations, we multiply the lower matrix with the right matrix. For convenience I'll refer to the lower matrix as C and the right matrix as R, with this layout:

IR
C

Multiply the C and R:

10-1
011
001
*
100
010
1/20-1/2
=
1/201/2
1/21-1/2
1/20-1/2

The result is equivalent to that obtained in the previous section. But combining row and column operations leads to other possibilities we'll investigate in the next section.